####
**Best Online Course :**
SAS Programming with 50+ Case Studies

- Explain Programming Concepts in Simple English

- Live Projects & Case Studies

- Job Placement Assistance

- Get 20% off till July 14, 2017

Most of us must find intersection of two linear straight lines with pen and paper during school days. In this article, we will see how to solve it with Excel.

Apply the following formulae :

X=(INTERCEPT(y-values2,x-values2)-INTERCEPT(y-values1,x-values1))/(SLOPE(y-values1,x-values1)-SLOPE(y-values2,x-values2))

and Y =SLOPE(y-values1,x-values1)*X+INTERCEPT(y-values1,x-values1)

**To find intersection of two straight lines:**- First we need the equations of the two lines.
- Then, since at the point of intersection, the two equations will have the same values of x and y, we set the two equations equal to each other. This gives an equation that we can solve for x
- We substitute that x value in one of the line
equations and solve it for y

**Let the lines follow a system of linear equations :**

**y1=m1x1+c1 and y2=m2x2+c2**

Where

m1: Gradient or Slope of line1,

c1: Intercept of line1,

m2: Gradient or Slope of line2,

c2: Intercept of line2

Let the point of intersection be s and t. They must satisfy the above 2 equations.

t=m1s+c1 and t=m2s+c2 . Then m1s+c1=m2s+c2

s= (c2-c1)/(m1-m2) , t=m1*s+c1

m1: Gradient or Slope of line1,

c1: Intercept of line1,

m2: Gradient or Slope of line2,

c2: Intercept of line2

Let the point of intersection be s and t. They must satisfy the above 2 equations.

t=m1s+c1 and t=m2s+c2 . Then m1s+c1=m2s+c2

s= (c2-c1)/(m1-m2) , t=m1*s+c1

Use

For example : I take the following equations :

y1 = 2.5x1 - 0.5

y2=-0.5x1+1.67

Based on the above equations i created data for y1 and y2 using same values on X1.

**SLOPE**and**INTERCEPT**functions to replicate these equations in excel.s=(INTERCEPT(y-values2,x-values2)-INTERCEPT(y-values1,x-values1))/(SLOPE(y-values1,x-values1)-SLOPE(y-values2,x-values2))

t =SLOPE(y-values1,x-values1)*X+INTERCEPT(y-values1,x-values1)

For example : I take the following equations :

y1 = 2.5x1 - 0.5

y2=-0.5x1+1.67

Based on the above equations i created data for y1 and y2 using same values on X1.

**Download the excel file****STEP I:**

**To find the intersection point :**

Apply the following formulae :

X=(INTERCEPT(y-values2,x-values2)-INTERCEPT(y-values1,x-values1))/(SLOPE(y-values1,x-values1)-SLOPE(y-values2,x-values2))

and Y =SLOPE(y-values1,x-values1)*X+INTERCEPT(y-values1,x-values1)

**STEP II:**

Insert Scatter with Straight lines chart and mark intersection point (

**Right click on lines >> Format Data series >> Marker Options / Fill**)**Click on the link below to download this file**

**Intersection between lines**

**Related link :**

**Intersection between curve and straight line**

Very good tutorial, helped a lot today! Thank you :)

ReplyDeletehello,

ReplyDeleteLet say i have a sinusoidal equation, y = A sin wt and a straight line equation, y = mt + c. how do i determine the intersection between those graphs?

Sorry, I am slow and got little from it. Perhaps, some practical examples would help. I have home with a roof with a 6:12 slope. I want to add a porch with a 4:12 slope. The porch (with eave) is 11.5 feet wide. How long will the rafter be from the porch's eave up the main roof to the interception point?

ReplyDeleteThank You.

ReplyDeleteHi, sir please tell us about yourself. Thanks a lot for this website.

ReplyDeleteThank you very much

ReplyDelete