This tutorial describes multiple ways to extract a unique or distinct list from a column.

Suppose you have a list of customer names. The list has some duplicate values. You wish to extract unique values from it. Unique values would be a distinct list.

Click on the link below and download the excel file for reference.

Hit

It's an excel macro to pull distinct values from a column in Excel.

**Scenario**Suppose you have a list of customer names. The list has some duplicate values. You wish to extract unique values from it. Unique values would be a distinct list.

**Sample File**Click on the link below and download the excel file for reference.

**Extract a unique list from a range****Solutions****1. Advanced Filter**

**Follow the steps shown below in the animation****STEPS**

- Go to
**Data**tab in the menu - In Sort and Filter box, Click
**Advanced**button - Choose
**"Copy to another location"** - In
**"List range :"**box, select a range from which unique values need to be extracted (including header) - In
**"Copy to :"**box, select a range in which final output to be put - Check
**Unique records only** - Click Ok

**2. INDEX-MATCH (Array Formula)**

Extract Unique Values - Formula |

**FORMULA**

**=IFERROR(INDEX($B$3:$B$15, MATCH(0,COUNTIF($D$2:D2, $B$3:$B$15), 0)),"")**

**Hit**

**CTRL+ SHIFT + ENTER**to confirm this formula. If done correctly, Excel will automatically place curly braces {...} around the formula.

After placing curly braces, the above formula would look like this :

{=IFERROR(INDEX($B$3:$B$15, MATCH(0,COUNTIF($D$2:D2, $B$3:$B$15), 0)),"")}

**Copy the above formula and paste it into cell D3. And paste it down till the cell D12 (Select the range D3:D12 and press Ctrl+D).**

**HOW TO USE**

**Follow the steps shown below in the animation****Version 2 : IF BLANK VALUES IN A LIST**

Suppose there are missing or blank values in your list from which you want to extract unique values. In this case, you need to tweak your formula. The modified formula is explained below -

Extract Unique Values given blank values |

**FORMULA**

**=IFERROR(INDEX($B$3:$B$15, MATCH(0,IF(ISBLANK($B$3:$B$15),1,COUNTIF($D$2:D2, $B$3:$B$15)), 0)),"")**

**Copy the above formula and paste it into cell D3. And paste it down till the cell D12 (Ctrl+D).**

Hit

**CTRL+ SHIFT + ENTER**to confirm this formula. If done correctly, Excel will automatically place curly braces {...} around the formula.

After placing curly braces, the above formula would look like this :

{=IFERROR(INDEX($B$3:$B$15, MATCH(0,IF(ISBLANK($B$3:$B$15),1,COUNTIF($D$2:D2, $B$3:$B$15)), 0)),"")}

It counts the number of cells within a range that meet the given condition

**How this formula works****Step 1 :****COUNTIF($D$2:D2, $B$3:$B$15)**

**Syntax :**COUNTIF(range, condition)It counts the number of cells within a range that meet the given condition

COUNTIF($D$2:D2, $B$3:$B$15) returns 1 if $D$2:D2 is found in $B$3:$B$15 else 0.

For example, for the second distinct record Dave, the formula becomes COUNTIF($D$2:D3, $B$3:$B$15). It is searching values D2 and D3 in the range B3:B15. The array becomes

={1;1;1;0;0;0;0;0;0;0;0;0;0}. It is 1 when values of D2 and D3 are found and 0 where it is not found.

**Step 2 :**In this step, we are checking the position of item that has an array value 0 in Step I.

**Syntax :**MATCH(lookup_value;lookup_array; [match_type]

It gives the relative position of an item in an array that matches a specified value.

MATCH(0,COUNTIF($D$2:D2, $B$3:$B$15), 0) returns 4 for the second distinct value. It is 4 because the value Dave is placed in the fourth position of the list. [Also see 0 is the fourth value of the step 1 array - {1;1;1;0;0;0;0;0;0;0;0;0;0}]

**Step 3 :**In this step, we extract the desired distinct value. The INDEX function helps to achieve it.

**Syntax :**INDEX(array,row_num,[column_num])

The INDEX function returns the reference of cell meeting row and column number in a given range.

INDEX($B$3:$B$15, MATCH(0,COUNTIF($D$2:D2, $B$3:$B$15), 0)) returns Dave.

**Tutorial : Excel Array Formula with Examples**

**3. MACRO (Advanced Filter)**

It's an excel macro to pull distinct values from a column in Excel.

**VBA CODE**

**HOW TO USE**

1. Press Alt + F11 to open VB editor window

2. Go to Insert menu >> Module

3. Copy and paste the above vba code into the window

**Download the workbook**

*I have added one more way to extract unique values from a range [Updated : June 2016]***4. Remove Duplicates Option**

The most easiest way to extract unique values from a range is to use

**"Remove Duplicates"**option. See the snapshot below -

Unique values : Remove Duplicates Option |

**Warning :**If you want to keep your original data (not overwrite unique values), make a copy of it (Paste original data to another range or tab) Otherwise original data would be removed.

Select range >> Go toData option>> Click onRemove Duplicates>> Select the column that contains duplicates >>Ok

**Important Note :**

- If you have multiple columns in a range and you want to remove duplicates based on a single column, make sure only the column that contains duplicates is selected.

Remove Duplicates by a column |

**Related Articles**

**1. Count Unique values in a column**

**2. Count Unique values in multiple columns**

**3. Select and Count Duplicate values in Excel**

Thanks a lot

ReplyDeleteIt works only for 1 column not for the 2d range

ReplyDeleteAny way to extend this over multiple columns?

DeleteConcatenate it and then run the concatenated column.

DeleteYou are a legend. Wish you all the best and keep up the good work.

ReplyDeleteExcellent.

ReplyDeleteNicely laid out; especially liked the multiple options to end results. However what I'm looking for is a formula that will seek out the first instance in a column with duplicate values and keep its row place at the same time. In all of your examples, the query column shows a condensed list that does not match across the rows the very first unique instance of that specific value.

ReplyDeleteA B

1 1

1

2 2

2

1

1

3 3

3

2

1

3

Use this formula...

Delete=IF(COUNTIF(A$2:A2,A2)=1,A2,"")

many many thanks dear...I was looking for this.

DeleteHey - it keeps returning "0" value rather than the text in the cells i want. Not sure what i am doing wrong.

ReplyDelete=IFERROR(INDEX('Pocketbook Data'!$C$12:$C$31,MATCH(0,COUNTIF('Chart of Accounts'!$B$4:B17,'Pocketbook Data'!$C$12:$C$31),0)),"")

Since it's an array formula, press CTRL SHIFT ENTER to confirm it rather than only ENTER.If done correctly, Excel will automatically place curly braces {...} around the formula.

DeleteI have the curly brackets and I pressed ctrl+d, but all I have are blank values.

DeleteUpload your file to cloud drive and share the link with me. Thanks!

DeleteI had the same issue Matt.

DeleteCheck if you have a circular reference on the bottom left status bar.

I needed to adjust the countif formula to reference the cell above the current cell that you are entering the formula into. This threw me originally as my data started on the first row of the sheet and Deepanshu's example starts on the second row.

i.e. My first formula was in cell n2 and the example formula references d2 because the first line is blank.

Further confusing is that when you evaluate the formula using formula auditing it looks to work right up to the last step when it switches from the correct value to zero.

HTH

Michael

Also thanks Deepanshu for taking the time to publish this information.

The =IFERROR(INDEX($F$13:$F$1353, MATCH(0,COUNTIF($X$12:X12, $F$13:$F$1353), 0)),"") perfectly worked for me except that I use a filter for the F column. When I deselect any item from the filtered column I would like to have it removed from the unique items list created.

ReplyDeleteIs that possible somehow?

Thanks in advance!

Dim d As Object, c As Variant, i As Long, lr As Long

ReplyDeleteSet d = CreateObject("Scripting.Dictionary")

Sheets("Plan1").Select

lr = Cells(Rows.Count, 1).End(xlUp).Row

c = Range("A1:A300" & lr)

For i = 1 To UBound(c, 1)

d(c(i, 1)) = 1

Next i

Sheets("Plan2").Select

Range("A1").Resize(d.Count) = Application.Transpose(d.keys)

This formula has helped me tremendously! However, is there a way to make the formula only return a value of a cell if the length of the value is 8 for example?

ReplyDeleteI have two spreadsheets, one has a column of data which contains varying lengths of text. On the other spreadsheet I am trying to populate a column with only the values that are a length of 8.

My goal is to NOT have to manipulate the data on the "source" spreadsheet as there will be others using this workbook and I just want to keep it as a simple copy/paste method for importing the raw data.

Any help would be appreciated.

=IFERROR(INDEX(PNRExport!$F$1:$F$800,MATCH(0,IF(ISBLANK(PNRExport!$F$1:$F$800),1,COUNTIF($F$5:F24,PNRExport!$F$1:$F$800)),0)),"")

I used your advice before and find this website extremely helpful, thank you.

ReplyDeleteNow I have a situation where a list has blanks and duplicates, very similar to your example “Version 2: IF BLANK VALUES IN A LIST” but here’s the catch . . . for this effort, I have a requirement to keep the duplicates for reporting purposes but remove the blanks. I might be over thinking this.

Here is the formula I’ve used but of course it removes duplicates which I need to keep:

{=IFERROR(INDEX(WIP!$A$3:$A$501, MATCH(0,IF(ISBLANK(WIP!$A$3:$A$501),1,COUNTIF($A$2:A55, WIP!$A$3:$A$501)), 0)),"")}

Do you have a simple way of achieving this?

Thank you.

ReplyDeleteHow can I do this from multiple list ranges from different worksheets, to get a list of unique model numbers, ranges being for example Sheet2!A2:A40, Sheet3!D2:D40, Sheet4!C5:C43, Sheet5!B2:B40. Thanks in advance!

ReplyDeleteMeant to clarify, it should always update Sheet1 column A with the unique list

ReplyDeleteHaving issues with this query it keeps returning 0 instead of the text. IF(ISERROR(INDEX(Invoiced!$B$1:$C$3101,SMALL(IF((Invoiced!$B$1:$B$3101=$A$5)*(COUNTIF($D$6:D6,Invoiced!$M$1:$M$3101)=0),ROW(Invoiced!$B$1:$B$3101)),ROW(1:1)),2)),"",INDEX(Invoiced!$B$1:$C$3101,SMALL(IF(Invoiced!$B$1:$B$3101=$A$5,ROW(Invoiced!$B$1:$B$3101)),ROW(1:1))*1,2))

ReplyDeleteThanks for providing these tips!

ReplyDeleteI'm trying do this across 3 columns, but there are no results. If I restrict the range to just one column than it works fine, but nothing for 3 columns.

Does this not work for multiple columns, and if not, is there any other alternative that does?

thanks!

Thank you very much! Your website has been SO helpful in my work! This formula is great, however sometimes I need Excel to extract the unique items in alphabetical order. For example, using your illustration above, is there a formula that would return the unique items in the order:

ReplyDeleteDave

Deepanshu

Jhonson

Neha

Sohan

...and not in the order that they occur in the column. I have a similar need with extracting values in ranked order, but have an existing workaround.

Any advice you could provide would be much appreciated!

Thanks again.

Another most simple way - button Data/Remove Duplicates.

ReplyDeleteAnimation for the first solution display it.

This comment has been removed by the author.

ReplyDeleteThis comment has been removed by the author.

ReplyDeleteThe vba gives me the first and second as duplicate...

ReplyDeleteAnd the first cell in the list has a name now Its called "Extract"

Any one has an idea why and how to fix?

super great

ReplyDeleteFantastic Trick to get a dynamic list. I'm a bit confused on how to extend the list beyond 15 rows. I've unsuccessfully changed all values from 15 to 40 rows, but it failed.

ReplyDeleteIf you are using advanced filter to extract unique values, you need to give reference of your updated range manually in the 'List Range' box

DeleteI'd like to use INDEX+MATCH '=IFERROR(INDEX($B$3:$B$15, MATCH(0,IF(ISBLANK($B$3:$B$15),1,COUNTIF($D$2:D2, $B$3:$B$15)), 0)),"")

DeleteChanging references from $B$15 to $b$30 does not pick up addl rows beyond row 15

I have changed the reference and it is working. The file is saved here - Working Sheet

DeleteMake sure you are changing reference from $B$15 to $B$30 in all the three places in the formula. Press CTRL SHIFT ENTER to confirm this formula rather than simple ENTER. If you do it correctly, you would see the formula enclosed in curly brackets.

Thank you for your quick response and for pointing out my omission to you CTRL SHIFT ENTER - all is well now

DeleteGlad to know all is well now. Cheers!

DeleteHi there,

ReplyDeleteIt works for me. But honestly I didn't get that formula. I would appreciate if someone helps me to understand.

Here is my understanding:

Index($E$2:$E$1000, Match(0,countif($A$3:A3,$E$2:$E$1000),0))

---To be specific this is the part I didn't understand---

countif($A$3:A3,$E$2:$E$1000) --- This function returns 0 or 1 if the value exist in $E$2:$E$1000 range.

Then comes

Match(0,countif($A$3:A3,$E$2:$E$1000),0) --- which is generating this value Match(0, 0 or 1, 0) How come Match function doesn't have a range in the middle. In fact its taking countif array as range. Could anyone explain this to me?

Trying to generate column C from data in A and B. Need to take first all same type in "A" and list first and last occurrence of same type in "a". Data is sorted by "A" then by "B".

ReplyDeleteA B c

1 Blue 24"x36" 24"x36' to 42"x66"

2 Blue 24"x8' 24"x36' to 42"x66"

3 Blue 42"x66" 24"x36' to 42"x66"

4 Red 24"x8' 24"x8' to 7'6"x9'6"

5 Red 7'6"x9'6" 24"x8' to 7'6"x9'6"

Sorry, removed my spacing...

Delete| Col A| Col B | Col C

1 | Blue | 24"x36" |24"x36" TO 42"x66"

2 | Blue | 24"x8' |24"x36' to 42"x66"

3 | Blue | 42"x66" |24"x36' to 42"x66"

4 | Red |24"x8' |24"x8' to 7'6"x9'6"

5 | Red |7'6"x9'6"|24"x8' to 7'6"x9'6"

Suppose values are placed in range A2:B6. Place the following formula in cell C2 and paste it down till C6.

Delete=INDEX($B$2:$B$6,MATCH(A2,$A$2:$A$6,0))&"to" &INDEX($B$2:$B$6,MATCH(A2,$A$2:$A$6))

thaks it worked

ReplyDeleteHow can I extract unique values to a different sheet altogether?

ReplyDeleteThere's a challenge after applying the above formulas. A window pops up which is titled Update Values :"File Name"

Any help in this regard will be greatly appreciated. Thanking u.

Huzefa.

I was racking my brain to come up with a clean solution for this - and your posting was most helpful. Thank you for saving me several hours of frustration! Really appreciated!

ReplyDeleteIn the duplicates list find out unique values stored in array. using vba program......

ReplyDeleteThank you for your code which is most usefull, need your kind assistance to modify formula in excel to work with countifs or by using index to return 2 values for example the stage column and user name

ReplyDeleteHi Dipanshu ,

ReplyDeleteThanks a lot for posting this - just one thing option 2 gives circular reference error

The formula works fine. Save your file to cloud drive and share link with me.

DeleteGood tutorial but VBA code doesnt work if you have formulas in selected columns which echo text in cells with IFs. The same is with other methods. This tricks work only if you have simple text in every cell or digits result if you use formulas in cells

ReplyDeleteSorry it works... my mistake... missing (,) in my code ;)

ReplyDeleteThank You

ReplyDeleteThanks for this thorough explanation. For some reason I am getting the same entry (the first) repeated over the entire column. Any help would be much appreciated!

ReplyDeleteThank you for writing to me. Save your file on cloud drive and share link with me.

DeleteHi,

ReplyDeleteI'm trying to figure it out: how can I extract (text) values from rows (they're always unique IN A ROW - it's rather filtering out cells with formulas returning "") to cells in columns, than proceed to next row(s) and do the same, BUT... in these other rows values are often THE SAME AS IN PREVIOUS ROWS!

What's more - I want values from first two columns to be repeated as long, as there are unique values from other columns being returned by formula...

From that [over 200 rows and over 80 columns]...

[001] | title 1 |A |"" |C |D |"" |F

[002] | title 2 |"" |B |C |D |E |""

[003] | title 3 |A |B |C |"" |E |F

I'd like to get this:

[001] title 1 A

[001] title 1 C

[001] title 1 D

[001] title 1 F

[002] title 2 B

[002] title 2 C

[002] title 2 D

[002] title 2 E

[003] title 3 A

[003] title 3 B

[003] title 3 C

[003] title 3 E

[003] title 3 F

Any help would be greatly appreciated! (And sorry for my english.)

Best regards.

I have a quick question perhaps you may help me. I have tried the solution using aggregate function but since my workbook is huge it is taking forever to load, when I use index and match it is super fast but I am failing to find a workaround of ignoring the zero values.

ReplyDeleteSample data is as follows

Date Acc# Join Check

01/Jan/2017 5014 42,277 Correct

1-Jan-2017 1047 - Not this

5-Jan-2017 1047 - Not this

15-Jan-2017 1047 42,308 But this

This is a student dataset in a school, so students have to pay a small registration fee which some pay once like Acc 5014 and some pay in installments as Acc 1047. The thing is the join date starts when the reg fee is fully paid hence the zeros on 1 and 5 jan 2017.

Thanks

Hello Deepanshu,

ReplyDeleteThe INDEX-MATCH example that you created was brilliant. Is CountIf() the only function that would have output that array for the match function? I'm having trouble understanding why the CountIf() function is even outputting an array at all. Sorry if my question is dumb, I've only recently begun using the Index function instead of Vlookup.

Thank you,

John